- #1
Moham1287
- 7
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1.The position of a particle x(t) obeys the following differential equation
d^2x/dt^2 + 4(dx/dt) + 3x = (3t/2) -4
If at t=0, both x=0 and dt/dx=0, find x(t)
Attempt at solution
I've found the homogeneous solution to be y=Aexp(-3x) + Bexp(-x), and know how to find x(t) given boundary conditions, but I'm having trouble finding the particular solution. I know you have to use g(x) where g(x) is the RHS of the equation, but when I try using Yp=r exp(mu x) or a combination of factors of x, I get a load of rubbish. Can anyone please help?
d^2x/dt^2 + 4(dx/dt) + 3x = (3t/2) -4
If at t=0, both x=0 and dt/dx=0, find x(t)
Attempt at solution
I've found the homogeneous solution to be y=Aexp(-3x) + Bexp(-x), and know how to find x(t) given boundary conditions, but I'm having trouble finding the particular solution. I know you have to use g(x) where g(x) is the RHS of the equation, but when I try using Yp=r exp(mu x) or a combination of factors of x, I get a load of rubbish. Can anyone please help?