- #1
Shay10825
- 338
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Hi everyone!
Find the extreme values of the function and where they occur. I have to do this without graphing them and without a calulator.
1.) y= sqrt( x^2 - 1 )
y'= [.5( x^2 -1)^ (-3/2)][2x]
y'= x / [(x^2 - 1)^(3/2)]
0 = x / [(x^2 - 1)^(3/2)]
Now what? I can't solve for x?
2.) y= (x^2 - 1)^-1
y' = -1 (x^2 -1) ^-2
0 = -1(x^2 - 1)^-2
x= -1 and 1?
Is this correct? If so how do I know which is the min and which is the max?
3.) y= 1/ sqrt(1- x^2)
y'=-1(sqrt(1 -x^2))^-2
0 = -1/ (1- x^2)
x = 1 and -1??
Is this correct? If so how do I know which is the min and which is the max?
~Thanks
Find the extreme values of the function and where they occur. I have to do this without graphing them and without a calulator.
1.) y= sqrt( x^2 - 1 )
y'= [.5( x^2 -1)^ (-3/2)][2x]
y'= x / [(x^2 - 1)^(3/2)]
0 = x / [(x^2 - 1)^(3/2)]
Now what? I can't solve for x?
2.) y= (x^2 - 1)^-1
y' = -1 (x^2 -1) ^-2
0 = -1(x^2 - 1)^-2
x= -1 and 1?
Is this correct? If so how do I know which is the min and which is the max?
3.) y= 1/ sqrt(1- x^2)
y'=-1(sqrt(1 -x^2))^-2
0 = -1/ (1- x^2)
x = 1 and -1??
Is this correct? If so how do I know which is the min and which is the max?
~Thanks