- #1
Abigale
- 56
- 0
Hello,
I regard field-operators, whereby [itex]\Psi[/itex] is a fermionic-annihilation-operator and
[itex]\vec{A(\vec{r})}[/itex] is an electromagnetic-vector-potential.
Is it possible to do the following step?
$$
\nabla \vec{A} \Psi =\Psi \nabla \vec{A} + \vec{A}\nabla\Psi
$$
And if its correct, why?
Thx
Abby
I regard field-operators, whereby [itex]\Psi[/itex] is a fermionic-annihilation-operator and
[itex]\vec{A(\vec{r})}[/itex] is an electromagnetic-vector-potential.
Is it possible to do the following step?
$$
\nabla \vec{A} \Psi =\Psi \nabla \vec{A} + \vec{A}\nabla\Psi
$$
And if its correct, why?
Thx
Abby