- #1
bs vasanth
- 16
- 1
The binding energy (BE) per nucleon for 235U is 7.6 Mev. The 235U undergoes a nuclear fission to produce two fragments both having a BE of 8.5Mev. What is the energy released from a complete fission of 1kg of 235U (joules)?
Here I assumed that it breaks into two 118X element. Therefore
BE(product) per atom is 2*118*8.5=2006
BE(reactant) per atom is 236*7.6=1793.6
Energy released per atom= 212.4 Mev
Number of atoms in 1 kg U=1/.235*6.022*[itex]10^{23}[/itex] = 2.5625*[itex]10^{24}[/itex]
Total energy = 2.5625*[itex]10^{24}[/itex] *212.4
= 5.4428*[itex]10^{26}[/itex] Mev
= 8.7*[itex]10^{13}[/itex] joules
I want know if my answer is correct ?
Here I assumed that it breaks into two 118X element. Therefore
BE(product) per atom is 2*118*8.5=2006
BE(reactant) per atom is 236*7.6=1793.6
Energy released per atom= 212.4 Mev
Number of atoms in 1 kg U=1/.235*6.022*[itex]10^{23}[/itex] = 2.5625*[itex]10^{24}[/itex]
Total energy = 2.5625*[itex]10^{24}[/itex] *212.4
= 5.4428*[itex]10^{26}[/itex] Mev
= 8.7*[itex]10^{13}[/itex] joules
I want know if my answer is correct ?