- #1
arimike
- 3
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Basic question here: I have a simple circuit consisting of a 12 vdc battery, a level switch and a water pump. The switch is rated for 1/4 HP @ 32 vdc, and the pump is 12 vdc rated at 15.5A.
If 1/4 HP = 185 watts, I assume that equals 5.8A @ 32 vdc, and is not capable of handling the motor load of 15.5A. Is this right?
I keep wondering if I am looking at this wrong because I see this exact motor/switch combination in use in various places...with the switch used to make/break the NEGATIVE line. What is the advantage of placing the switching mechanism on the negative side of a DC circuit?
Any insight would very appreciated!
If 1/4 HP = 185 watts, I assume that equals 5.8A @ 32 vdc, and is not capable of handling the motor load of 15.5A. Is this right?
I keep wondering if I am looking at this wrong because I see this exact motor/switch combination in use in various places...with the switch used to make/break the NEGATIVE line. What is the advantage of placing the switching mechanism on the negative side of a DC circuit?
Any insight would very appreciated!