- #1
Ivegottheskill
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The question I've been attempting:
From my notes and working etc. I've got:
E = lambda/2*pi*epsilon*r (where lambda = charge per unit length and epsilon = permittivity of free space)
F = E * q (where q = the charge of the proton, -1.60*10^-19, as apparently defined by the question)
I've used the F calculated to get acceleration by
a = F/m (where m = mass of proton)
I get a value of -7.88*10^7
I then use the linear acceleration formula v^2 = u^2 + 2*a*s to try and calculate s.
I get 0.04627... (4.63*10^-2)
Apparently this is incorrect however. Can anyone see where I'm messing up?
An infinitely long line of charge has a linear charge density of 8.00×10−12 C/m. A proton is a distance of 17.5 cm from the line and moving directly toward the line with a speed of 2700 m/s.
How close does the proton get to the line of charge?
Use 1.60×10−19 C for the magnitude of the charge on an electron, 1.67×10−27 kg for the mass of a proton, and 8.85×10−12 F/m for the permittivity of free space
From my notes and working etc. I've got:
E = lambda/2*pi*epsilon*r (where lambda = charge per unit length and epsilon = permittivity of free space)
F = E * q (where q = the charge of the proton, -1.60*10^-19, as apparently defined by the question)
I've used the F calculated to get acceleration by
a = F/m (where m = mass of proton)
I get a value of -7.88*10^7
I then use the linear acceleration formula v^2 = u^2 + 2*a*s to try and calculate s.
I get 0.04627... (4.63*10^-2)
Apparently this is incorrect however. Can anyone see where I'm messing up?