Explanation Needed for Equation for Gravitation/Conservation of Energy equation

In summary, this conversation discusses the radial distance a projectile reaches when shot directly away from Earth's surface with an initial speed of 1/2 of the escape speed. The equation for conservation of energy is used to find the correct equation for this scenario, which includes the term GMm/r for potential energy at the peak of the projectile's motion. The last equation mentioned is for an object already in orbit, not for something being shot into orbit.
  • #1
auk411
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Homework Statement


A projectile is shot directly away from Earth's surface. Neglect rotation of Earth. What multiple of Earth's radius R_e gives the radial distance a projectile reaches if its initial speed is 1/2 of the escape speed from Earth.


Homework Equations



Ki + Ui = Kf + Uf,
where K is the kinetic energy and u is the gravitational potential energy.

v0 =[tex]\sqrt{Gm/2R}[/tex] ... this is the initial velocity when its initial speed is 1/2 of the escape speed.

The Attempt at a Solution



We know that energy is conserved. Then what I do is:

[tex]\frac{1}{2}[/tex]mv02 - [tex]\frac{GMm}{R_e}[/tex] = 0

I plug in v0 =[tex]\sqrt{Gm/2R}[/tex] for v0 in the previous equation. I do not get the right answer. What is wrong with this equation?

Apparently, this is the right equation:

[tex]\frac{1}{2}[/tex]mv02 - [tex]\frac{GMm}{R_e}[/tex] = [tex]\frac{GMm}{r}[/tex], where r is just some radial distance from earth.

Now, I do not understand where [tex]\frac{GMm}{r}[/tex] comes from.

Also, why doesn't the [tex]\frac{1}{2}[/tex]mv02 - [tex]\frac{GMm}{R_e} =\frac{-GMm}{2r}[/tex], since that is what my textbook says is what the total mechanic energy is for satellites. Isn't this thing going to be become a satellite? So why couldn't I use the aforementioned equation?
 
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  • #2
Initially on the surface of the earth, the projectile has both kinetic and potential energy. Now at the peak of it's motion, the projectile has lost all its kinetic energy which has been converted totally into potential energy. That's where the GMm/r on the right hand side of the equation comes from.

For your last question, that equation is for an object which is already in orbit, not for something which is shot from the Earth into orbit. That equation enables us to find the speed at which the satellite is moving around the Earth if we know the altitude of the satellite. You wrote the equation wrongly too. Its

[tex]\frac{1}{2}mv^2-\frac{GMm}{r}=-\frac{GMm}{2r}[/tex]

in which both r's are the distance of the satellite from the center of the earth.
 
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1. What is the equation for gravitation?

The equation for gravitation is known as Newton's Law of Universal Gravitation, which states that the force of attraction between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

2. How is the equation for gravitation derived?

The equation for gravitation was derived by Sir Isaac Newton in the 17th century through his observations and experiments with falling objects and planetary motion. He combined his laws of motion with the concept of gravitational force to create the equation.

3. What is the significance of the conservation of energy equation?

The conservation of energy equation, also known as the first law of thermodynamics, states that energy cannot be created or destroyed, but can only be converted from one form to another. This is important because it explains the fundamental principle of energy and its role in all physical processes.

4. How does the conservation of energy equation relate to the equation for gravitation?

The conservation of energy equation can be used to explain the equation for gravitation. As objects move closer together due to gravitational force, their potential energy decreases while their kinetic energy increases, thus conserving the total energy of the system.

5. Can the equation for gravitation be applied to all objects in the universe?

Yes, the equation for gravitation can be applied to all objects in the universe, regardless of their size or mass. This is because gravity is a universal force that acts on all objects with mass, and the equation takes into account the masses and distances between objects in order to calculate the force of gravity.

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