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EtherMD
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Homework Statement
A proton (m=1.67x10^-27) is suspended at rest in a uniform electric field E. Take into account gravity and determine E.
Homework Equations
FE=|q|E
Fg=mg
The Attempt at a Solution
FG = mg
FG = (1.67x10-27)(9.8)
FG = 1.64 x 10-26
Since the force on the proton due to the E field is equal and opposite, then:
FE=|q|E
FE / q= E
(1.64x10-26) / (1.6x10-19) = E
1.04x10-9 = E
Is my work correct?