- #1
John 123
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Homework Statement
I am a bit rusty on parabolae.
I am doing a question on projectiles and have found the coordinates of the vertex of a parabola as:
[tex]
(\frac{(v_0)^2\sin\alpha\cos\alpha}{g},\frac{(v_0)^2(\sin^2\alpha)}{2g})
[/tex]
The question now requires you to show that the distance from the vertex to the focus is given by:
[tex]
\frac{(v_0)^2(\cos^2\alpha)}{2g}
[/tex]
and that the equation of the directrix is
[tex]
y=\frac{(v_0)^2}{2g}
[/tex]
John