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ruiwp13
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Homework Statement
∫x^3*√(x^2-5) dx
Homework Equations
∫u.dv=u.v-∫du.v
The Attempt at a Solution
So i tried to change the integral to ∫x*x^2*√(x^2-5)dx and u = x^2-5, then du = 2x, so 1/2*∫x^2*√(x^2-5) . Let u = √(x^2-5) , du = x/√(x^2-5) and dv = x^2 , v = x^3/3. Am I going in the right direction?
Thanks in advance
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