- #1
am08
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Two blocks are in contact on a frictionless table. A horizontal force F is applied to M2, as shown. If M1 = 1.51kg, M2 = 3.96kg, and F = 4.55N, find the size of the contact force between the two blocks.
So first I found the acceleration (F=ma)
4.55/(1.51+3.96) = 0.83 = acceleration
Im suck from here
So first I found the acceleration (F=ma)
4.55/(1.51+3.96) = 0.83 = acceleration
Im suck from here