Why can't optical phonons travel far?

In summary, acoustic phonons are low loss because they do not coincide with the size of the molecules/atoms, and dissipation of energy due to resonance and electron-phonon coupling plays a role.
  • #1
joelio36
22
1
I can't figure this out/find the answer. Why are acoustic phonons very low loss (i.e. earthquake P and S waves), but optical phonons die out rapidly?

Thanks,
Joel
 
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  • #2
What mechanisms have you considered?
In what sense are phonons "low loss"? What does that mean exactly?
 
  • #3
The energy loss is low is because of the low frequency/longer wavelength phonon - which does not coincide with the size of the molecules/atoms. The higher frequencies/shorter wavelength phonon is likely to coincide with the size of the molecules/atoms, and thus losing its energy through resonating the energy through all the molecules/atoms. This is the cause of energy attenuation.

Another factor is energy dissipation: By having the size of molecules/atoms coinciding close to that of the phonon, the phonon streams is more likely to be reflected/refracted and thus dissipated.

Both of these factors can help to explain why longer wavelength can travel far, low signal loss.

Another possible explanation is the phonon density: higher frequencies phonon matches with that of smaller atoms/molecular structures, which occurred at a higher density/number, and thus is able to spread the energy faster. Lower frequencies/longer wavelength need larger molecular structures (or multiple atom forming a macro-structures), which occur at a much lower densities, and thus is less able to spread the energy faster.

Another possible dissipative phenomena is electron-phonon coupling, which is more likely to happen for higher frequencies phonons.

These are my layman's perspective of what's happening, but from a specialist point of view (beyond me), u can refer to:

http://www.iop.vast.ac.vn/theor/conferences/nctp/proc/35/153.pdf (on resonance)

http://ocw.mit.edu/courses/chemistr...y-ii-spring-2008/lecture-notes/23_562ln08.pdf (which correlate the wavelength of the phonon with the size of the molecule/atom)

and

http://www-ee.eng.buffalo.edu/faculty/mitin/Papers/115.pdf (on electron-phonon coupling)

http://www.iue.tuwien.ac.at/phd/smirnov/node53.html

http://www.uni-tuebingen.de/meso/ssscript/phononen.pdf

http://ndl.ee.ucr.edu/Paris-Lecture-05.pdf
 
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1. Why do optical phonons have a limited travel distance?

Optical phonons have a limited travel distance because they are highly localized vibrations of the crystal lattice, and their energy is easily dissipated through interactions with defects and impurities in the crystal structure.

2. What is the relationship between optical phonons and thermal conductivity?

Optical phonons have a direct impact on thermal conductivity because they contribute to the transfer of heat through the crystal lattice. However, their limited travel distance can also hinder the overall thermal conductivity of a material.

3. Can optical phonons travel through all types of materials?

No, optical phonons can only exist in materials with a crystal lattice structure, such as metals, semiconductors, and insulators. Amorphous materials do not have a defined crystal structure and therefore cannot support optical phonons.

4. How do defects and impurities affect the travel distance of optical phonons?

Defects and impurities in the crystal structure can scatter and absorb optical phonons, reducing their travel distance. This is because these imperfections disrupt the regular vibrations of the crystal lattice, making it more difficult for the phonons to propagate.

5. Is there any way to increase the travel distance of optical phonons?

Yes, the travel distance of optical phonons can be increased by reducing the number of defects and impurities in the crystal lattice. This can be achieved through careful material preparation and processing techniques. Additionally, certain crystal structures, such as diamond, have a higher phonon travel distance compared to others.

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