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kimikims
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An object is thrown vertically upward such that it has a speed of 58 m/s when it reaches two thirds of it's maximum height above the launch point.
The acceleration of gravity is 9.8 m/s^2
Find the maximum height h. Answer in units of m.
I know:
V: 58 m/s at y=2/3 H
H = ?
V = 0
V^2-Vo^2 = 2g(1/3H)
I know I need to plug in the numbers, but how do I get all of the equation to one side, to find H??
The acceleration of gravity is 9.8 m/s^2
Find the maximum height h. Answer in units of m.
I know:
V: 58 m/s at y=2/3 H
H = ?
V = 0
V^2-Vo^2 = 2g(1/3H)
I know I need to plug in the numbers, but how do I get all of the equation to one side, to find H??