Newton's Laws; ramps and pulleys

In summary, the weight of the block causes it to accelerate down a ramp, and the equation for the acceleration is F=ma.
  • #1
glacialis
3
0

Homework Statement


http://img201.imageshack.us/img201/6315/diagramyk1.gif
-Assuming the system is frictionless, find m2 when it is accelerating down the ramp at 3.4 m/s2.

Homework Equations


-... F = ma?

The Attempt at a Solution


-In this problem, I tried tilting the axis so the sliding-down part aligned with the y-axis and the m1 part on the x-axis. Then, I thought of using the components to the Fw, to figure out the Tension on the rope for the m2 side (which, I guessed, to be m2a.).
I couldn't figure out what to make the Tension equal to, because m2gcos([tex]\theta[/tex]) wasn't coming out the same as 3.4*m2.

...I then realized I was quite retarded at physics (I'm being perfectly honest, now.) and needed help.
 
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  • #2
did you make the free body diagram?
 
  • #3
oh, sorry! I forgot to attach it... >_<;;;

http://img297.imageshack.us/img297/3359/diagram2im0.gif

I suppose what confuses me is the fact that they're on ramps; I don't know how/where to draw the gravity part.

(apologies if this is frustrating for you. I'm just really bad at physics.)
 
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  • #4
nooooooooooo
this is what a free body diagram for such a situation looks like.
now make the other one. write the appropriate equation ie. Fnet = m*a.
eliminate T from both the equations. you have "a", find "m" and show us what you got. ok??
 

Attachments

  • fbd.PNG
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  • #5
The weight acts at the centre of gravity (mass) of the block.
 
  • #6
i guess OP is asking the direction of gravitational force andrevdh
 
  • #7
(well, my retardation may have reached a new low.)

I figured out how to do the free-body diagram right this time, and got:

http://img254.imageshack.us/img254/5139/diagramca9.gif

[tex]\Sigma[/tex]Fx = m2gsin[tex]\alpha[/tex] - T = m2a.
and
[tex]\Sigma[/tex]Fx = T- m1gsin[tex]\beta[/tex] = m1a.

so if I solve for T it would be m1a + m1gsin[tex]\beta[/tex], and substitute that into the first equation to figure out m2a.

with grouping like terms, plugging in numbers, solving, &c, I got 11.0 kg.

...would that be right?

(and a big thank you for the help!)
 
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  • #8
i didnt calculate the values, but the method you described, answer should be alright.
 

1. What are Newton's Laws of motion?

Newton's Laws of motion are a set of three physical laws that describe the behavior of objects in motion. They were formulated by Sir Isaac Newton in the late 17th century and are fundamental to understanding the principles of mechanics.

2. How do Newton's Laws apply to ramps?

Newton's Laws apply to ramps in the same way they apply to any other object in motion. The first law states that an object will remain at rest or in constant motion unless acted upon by an external force. When an object is on a ramp, the force of gravity is acting upon it, causing it to roll or slide down the ramp.

3. How does friction affect objects on a ramp?

Friction is a force that opposes motion and can affect objects on a ramp in various ways. The amount of friction present on a ramp depends on the roughness of the surface and the weight of the object. Friction can help objects stay in place on a ramp, but it can also slow down the object's motion.

4. What is the role of pulleys in Newton's Laws?

Pulleys are simple machines that can be used to change the direction of a force or to multiply the force applied. In terms of Newton's Laws, pulleys can help reduce the amount of force needed to lift an object by distributing the weight across multiple ropes and pulleys.

5. How do ramps and pulleys work together to make work easier?

Ramps and pulleys work together to make work easier by reducing the amount of force needed to lift or move objects. By using a ramp, the force needed to lift an object is spread out over a longer distance, making it easier to overcome. And by using pulleys, the force needed to lift an object can be distributed across multiple ropes and pulleys, making it even easier to lift heavy objects.

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