- #1
Kandycat
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Homework Statement
A 22.0-cm-diameter coil consists of 20 turns of circular copper wire of 2.6 mm in diameter. A uniform magnetic field, perpendicular to the plane of the coil, changes at a rate of 8.65 x 10-3 T/s. Determine (a) the current in the loop, and (b) the rate at which thermal energy is produced.
Homework Equations
V = NBA / t
R= pl/A
l = N*2*pi*diameter of coil
A = pi*(radius of wire)2
I = V/R
The Attempt at a Solution
I understand the part (a)... sort of. Tell me if I did it something wrong.
V = NBA / t
V = (20)(8.65 x 10-3 T/s)(pi*(.0013 m)2) = 9.19 x 10-3 V
R = pl/A
R = (1.72 x 10-8)(20*2*pi*.22 m)/ (pi*(.0013 m)2) = 8.96 x 10-2 ohms
I = V/R
I = 9.19 x 10-3 V / 8.96 x 10-2 ohms = 1.03 x 10-5 A
Part (b) I don't understand. I don't know what I'm finding.