- #1
alpha01
- 77
- 0
for g(x) = (x-2) / (x^2 -9)
the domain of the function would be simply to have the denominator not equal to 0, which in this case would be x = 3.
but.. the solution states that it is -3 and 3 cannot be used.
this is confusing seeing that -3^2 -9 = -18 which is not 0.
maybe it means |-3|?
the domain of the function would be simply to have the denominator not equal to 0, which in this case would be x = 3.
but.. the solution states that it is -3 and 3 cannot be used.
this is confusing seeing that -3^2 -9 = -18 which is not 0.
maybe it means |-3|?
Last edited: