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An answer to https://www.physicsforums.com/showthread.php?t=31826
Let us add Lorenz transformation to our "story".
So there is no difference between observer1 and observer2 because space scale shrinks like a rubber sheet without losing its density ( exactly as (x/1)*(1/x) = 1 ) in the direction of the movement of observer2, and expends in the opposite side of observer2.
These opposite states can be observed as Doppler Effect.
So in both cases the speed of light is invariant in both directions.
Let us add Lorenz transformation to our "story".
Code:
observer1
|(->[COLOR=YellowGreen]__.__.__.__.__[/COLOR](o)[COLOR=YellowGreen]__.__.__.__.__[/COLOR]<-)|
|(->[COLOR=YellowGreen]__.__.__.__.__[/COLOR](o)[COLOR=YellowGreen]__.__.__.__.__[/COLOR]<-)|
|(->[COLOR=YellowGreen]__.__.__.__.__[/COLOR](o)[COLOR=YellowGreen]__.__.__.__.__[/COLOR]<-)|
|(->[COLOR=YellowGreen]__.__.__.__.__[/COLOR](o)[COLOR=YellowGreen]__.__.__.__.__[/COLOR]<-)|
observer2
|(->[COLOR=YellowGreen]__.__.__.__.__[/COLOR](o)[COLOR=YellowGreen]__.__.__.__.__[/COLOR]<-)|
|(->[COLOR=Orange]___.___.___.___._[/COLOR](o)->[COLOR=teal].__.__.__[/COLOR]<-)|
|(->[COLOR=Red]____.____.____.____.[/COLOR](o)->[COLOR=Blue]_._._.[/COLOR]<-)|
|(->[COLOR=DarkRed]______.______.______.__[/COLOR](o)->[COLOR=Magenta]...[/COLOR]<-)|
So there is no difference between observer1 and observer2 because space scale shrinks like a rubber sheet without losing its density ( exactly as (x/1)*(1/x) = 1 ) in the direction of the movement of observer2, and expends in the opposite side of observer2.
These opposite states can be observed as Doppler Effect.
So in both cases the speed of light is invariant in both directions.
Last edited: