- #1
wendo
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Homework Statement
An electron is projected at an angle of 31.7° above the horizontal at a speed of 8.40×10^5 m/s in a region where the electric field is E = 383j N/C. Neglecting the effects of gravity, calculate the time it takes the electron to return to its initial height.
Homework Equations
I first found the electric force that the E field exerts on the electron by using F=qE.
Then I found the acceleration of the electron with a=(q/m)E
Thought perhaps electron would undergo motion similar to a projectile, so then first found the y component of the velocity sin 31.7=opp/8.40x10^5s.
Then applied vf=vi + at solving for t (with vf=0 because it will be when the electron has all potential energy at its highest point)
The Attempt at a Solution
F=383x(-1.6x10^-16C)
=-6.13x10^-14N
a=-6.13x10^-14N/9.11x10^-31kg (mass of electron)
=-6.73x10^16m/s^2
sin 31.7=opp/8.40x10^5m/s
opp= 4.41x10^5m/s
vf=vi +at
0=4.41 + -6.73x10^16m/s^2t
t=6.55x10^-12s (this would be the time to reach max height, so the amount of time to get back down to its initial height would be double this)
so t= 1.31x10^-11s
But this answer is not right... and I'm not show how else to relate t to an electric field. Can anyone point out what I'm doing wrong here??
Thanks SOOO much! :)