Bottle Rocket Velocity: Constant Force, Increasing Rate

  • Thread starter jerryez
  • Start date
  • Tags
    Force
In summary, the black powder burns out as the bottle rocket is launched, causing the mass of the rocket to decrease. This decrease in mass leads to an increase in the rate of change of velocity, even though the force propelling the rocket remains constant.
  • #1
jerryez
20
0

Homework Statement

A bottle rocket is launched in the air. The black powder, which propels it, burns leaving an exhaust trail mainly consisting of CO2 gas. If the force propelling the rocket is constant, the rate of change in its velocity INCREASES.

Can someone please explain why the change in its velocity increases. I was thinking since the force propelling the rocket is constant the rate of change in its velocity is ZERO. ?



Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
  • #2
The black powder burns out so the mass of the whole rocket decreases. ehild
 
  • #3
The black powder burns out so the mass of the whole rocket decreases.


ehild
 

1. What is bottle rocket velocity?

Bottle rocket velocity refers to the speed at which a bottle rocket moves through the air.

2. How is bottle rocket velocity affected by a constant force?

A constant force applied to a bottle rocket will result in a constant acceleration, causing the rocket to increase in velocity at a steady rate.

3. What happens to bottle rocket velocity when the force is increased?

Increasing the force applied to a bottle rocket will result in a higher acceleration, causing the rocket to increase in velocity at a faster rate.

4. Is bottle rocket velocity affected by other factors besides force?

Yes, bottle rocket velocity can also be affected by factors such as the design and weight of the rocket, air resistance, and the amount of fuel used.

5. How can bottle rocket velocity be calculated?

Bottle rocket velocity can be calculated by using the formula v = u + at, where v is the final velocity, u is the initial velocity (usually 0), a is the acceleration, and t is the time elapsed.

Similar threads

  • Introductory Physics Homework Help
Replies
2
Views
232
  • Introductory Physics Homework Help
Replies
10
Views
669
  • Introductory Physics Homework Help
Replies
2
Views
1K
  • Introductory Physics Homework Help
Replies
8
Views
3K
  • Introductory Physics Homework Help
Replies
6
Views
2K
  • Introductory Physics Homework Help
Replies
3
Views
1K
  • Introductory Physics Homework Help
Replies
22
Views
2K
  • Introductory Physics Homework Help
Replies
5
Views
1K
Replies
17
Views
946
  • Introductory Physics Homework Help
Replies
1
Views
2K
Back
Top