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xewe
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This is NOT homework.
In the FBD above, there is no friction, the velocity is constant, and the distance traveled by the box is 10 m horizontally. Find the work exerted on the object horizontally.
if f = 0, and a = 0 because of constant velocity,
ΣFx = ma = Fapp (cos 40) - f
200 kg (0) = Fapp (cos 40) -f
0 = Fapp (cos 40) - f
Fapp (cos 40) = f = 0
thus,
Fapp (cos 40) = 0
does this mean: Work = Fapp (cos 40) (d)
W = 0 (10 m)
W = 0
is this possible, to have no force but achieve distance?
Hi, by the way, I am new here. :)
This is NOT homework.
In the FBD above, there is no friction, the velocity is constant, and the distance traveled by the box is 10 m horizontally. Find the work exerted on the object horizontally.
if f = 0, and a = 0 because of constant velocity,
ΣFx = ma = Fapp (cos 40) - f
200 kg (0) = Fapp (cos 40) -f
0 = Fapp (cos 40) - f
Fapp (cos 40) = f = 0
thus,
Fapp (cos 40) = 0
does this mean: Work = Fapp (cos 40) (d)
W = 0 (10 m)
W = 0
is this possible, to have no force but achieve distance?
Hi, by the way, I am new here. :)