- #1
polly06
- 3
- 0
My question is:
If a car is moving at 33m/s^-1 down a 20 degree slope, the friction between car tires and the road surface is 0.58, what is the shortest distance and time in which it can stop?
I assume that Fmax= u R is correct formula?
(where Fmax=force max, u=coeff of friction, and R= normal reaction)
I also assume that R = mgsin20
(where m=mass, g=9.8, sin 20 for angle of slope)
Any help would be much appreciated!
thanks
-Polly
If a car is moving at 33m/s^-1 down a 20 degree slope, the friction between car tires and the road surface is 0.58, what is the shortest distance and time in which it can stop?
I assume that Fmax= u R is correct formula?
(where Fmax=force max, u=coeff of friction, and R= normal reaction)
I also assume that R = mgsin20
(where m=mass, g=9.8, sin 20 for angle of slope)
Any help would be much appreciated!
thanks
-Polly
Last edited by a moderator: