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Bachelier
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Can you guys provide a counter example of why this statement is False.
If T: V-->V with V a VS over C then T has an eigenvector?
This is not always true as if V is infinite dim., it'll have a Spectrum.
Any counter examples?
Thanks
If T: V-->V with V a VS over C then T has an eigenvector?
This is not always true as if V is infinite dim., it'll have a Spectrum.
Any counter examples?
Thanks
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