- #1
admiralgman
- 1
- 0
I need some help understanding inverse functions, we've had a 4-page chapter covering the basics of inverse functions and I understand that.
But now we have suddenly gotten these task that I don't understand how to solve, I've read the part on inverses several times, but I still don't understand.
To explain my trouble, here are two examples from my textbook that covers what I am struggeling with:
1:Calculate the inverse of the given functions in terms of f-1
g(x)=f(x)-2
(answer to this should be g-1(x)=f-1(x+2))
2: Find g-1(1) if g(x)=x3+x-9
(answer to this should be 2)
As you see I know the answers, this because they are in the back of my textbook. But I want some help understanding how you get from that point A to B
Also, it would be nice if you could show it in a step-by-step way as I am (already) having some trouble understanding the technical terms in english, considering I am from Norway
As a last bit of information; I will be gone for two hours or so now(Im a busy man), but it would be nice to come back here and see something that would help me understand "advanced" inverses.
But now we have suddenly gotten these task that I don't understand how to solve, I've read the part on inverses several times, but I still don't understand.
To explain my trouble, here are two examples from my textbook that covers what I am struggeling with:
1:Calculate the inverse of the given functions in terms of f-1
g(x)=f(x)-2
(answer to this should be g-1(x)=f-1(x+2))
2: Find g-1(1) if g(x)=x3+x-9
(answer to this should be 2)
As you see I know the answers, this because they are in the back of my textbook. But I want some help understanding how you get from that point A to B
Also, it would be nice if you could show it in a step-by-step way as I am (already) having some trouble understanding the technical terms in english, considering I am from Norway
As a last bit of information; I will be gone for two hours or so now(Im a busy man), but it would be nice to come back here and see something that would help me understand "advanced" inverses.