- #1
atomicpedals
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Homework Statement
For copper we find that J=[tex]\sigma[/tex]E , where [tex]\sigma[/tex] has the value 5.8x10^7 mksc units. If an alternating electric field represented by E0ei[tex]\omega[/tex]t exists within the copper. Find the ratio of the conduction to the displacement current density at a frequency of 1megacycle/sec.
Homework Equations
J=[tex]\sigma[/tex] dE0/dt
The Attempt at a Solution
So I'm hoping this is a straight forward as I'm making it out to be, minus my own issues with the units. I think it follows like this, but it seems too easy!
Please excuse my tex failures below...
J=[tex]\sigma[/tex] dE0/dt = i[tex]\omega[/tex][tex]\sigma[/tex]E0
[tex]\omega[/tex][tex]\sigma[/tex]E0=E0/J = 1.04x10^12