- #1
Punkyc7
- 420
- 0
set up a triple integral for the moment of inertia Iz for the region inside the sphere
x^2+y^2+z^2=4a^2 and inside the cylinder
x^2+y^2-2ax=0
so I draw my picture and convert to cylindrical coord. and i get an integral from 0 to sqrt(4a^2-r^2)
an integral from 0 to 2acostheta and an integral from 0 to 2pi
then I multiply by 2 becuase its only the top part of the volume that i set up and the integral is integrating r^3
my question is the answer says that the theta limits and goes from 0 to pi , so why is that?
x^2+y^2+z^2=4a^2 and inside the cylinder
x^2+y^2-2ax=0
so I draw my picture and convert to cylindrical coord. and i get an integral from 0 to sqrt(4a^2-r^2)
an integral from 0 to 2acostheta and an integral from 0 to 2pi
then I multiply by 2 becuase its only the top part of the volume that i set up and the integral is integrating r^3
my question is the answer says that the theta limits and goes from 0 to pi , so why is that?
Last edited: