- #1
Neitrino
- 137
- 0
Dear PF,
Could anyone help me to understand the following issue:
I don't understand the formation of Goldston bosons in chiral symmmetry breaking. Namely - suppose there is only fermion fields Lagrangian and due to some reasons the fermion field obteins VEV - <0|psi^bar psi|0> is non zero. And left/right chiral symmetry is reduced to its diagonal group.
I don't understant how Goldstone bosons are formed - I mean as folows"
In Scalar field case if we have multiple fields phi1, phi2, phi3... and when
this scalalar field develops some VEV - v, then for convience we can put only phi1 equals to this VEV -v, rest fields we can put zero...we will say this VEV of field phi1 is v, VEVs of rest field are zero: <0|phi1|0>=v,
<0|phi2|0>=0 etc. We say we have phi1 massive scalar field and rest Goldsone Bosons from Broken Symmetry.
So I don't understand what happens when suppose fermion fields develop VEV.
Thanks
George
Could anyone help me to understand the following issue:
I don't understand the formation of Goldston bosons in chiral symmmetry breaking. Namely - suppose there is only fermion fields Lagrangian and due to some reasons the fermion field obteins VEV - <0|psi^bar psi|0> is non zero. And left/right chiral symmetry is reduced to its diagonal group.
I don't understant how Goldstone bosons are formed - I mean as folows"
In Scalar field case if we have multiple fields phi1, phi2, phi3... and when
this scalalar field develops some VEV - v, then for convience we can put only phi1 equals to this VEV -v, rest fields we can put zero...we will say this VEV of field phi1 is v, VEVs of rest field are zero: <0|phi1|0>=v,
<0|phi2|0>=0 etc. We say we have phi1 massive scalar field and rest Goldsone Bosons from Broken Symmetry.
So I don't understand what happens when suppose fermion fields develop VEV.
Thanks
George