Newton's Law: Solve Force on Car & Trailer

In summary, Homework Equations state that the net force exerted by the car on the trailer is 1080N. The force exerted by the trailer on the car is 540N and the net force acting on the car is 1080-540=550N.
  • #1
laurenflakes
8
0

Homework Statement


On vacation, your 1300 kg car pulls a 540 kg trailer away from a stop light with an acceleration of 2.00 m/s2.
(a) What is the net force exerted by the car on the trailer?
(b) What force does the trailer exert on the car?
(c) What is the net force acting on the car?

Homework Equations


Force= mass x accelleration


The Attempt at a Solution



I was able to solve for part b by applying the above equation and doing the following:

(540)(2.00)=F so F=1080.

This answer was correct.. however when applying the same logic to part a)

(1300)(2.00)= 2600 ... the answer came out incorrect... I am not sure what I am doing wrong?

For part c I tried subtracting the force of the trailer from the force of the car to get the net force.. this too was incorrect. I am not sure what I am missing here.. please help?
 
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  • #2
Welcome to PF!

Hi laurenflakes! Welcome to PF! :smile:
laurenflakes said:
… I was able to solve for part b by applying the above equation and doing the following:

(540)(2.00)=F so F=1080.

This answer was correct.. however when applying the same logic to part a)

(1300)(2.00)= 2600 ... the answer came out incorrect... I am not sure what I am doing wrong?

For part c I tried subtracting the force of the trailer from the force of the car to get the net force.. this too was incorrect. I am not sure what I am missing here.. please help?

You're sort-of doing b) and c) in the wrong order …

F = ma gives you the net force on the body (net force means total force, not the applied force).

For the trailer, there's only one (horizontal) force, so you can't make a mistake.

But for the car, there are two forces (the rope and the engine), so you can make a mistake …

and you did! :wink:
 
  • #3
Thank you so much for replying! But I'm sorry I'm still confused (I'm very new at this so you will have to forgive me!)

For part a) it is asking the net force exerted by the car on the trailer.. and because the car is 1300 kg and the acceleration is 2.00m/s squared then I am not sure why I cannot just multiply these to get the Force of the car?

For part c) it is asking for the net force acting on the car, so I am thinking that I would add the force of the car and the force of the trailer? (I guess the problem is I cannot get the force of the car :-/ )

I would really really appreciate any further explanation anyone has to offer.. I can't seem to wrap my brain around this one.. Thanks!
 
  • #4
laurenflakes said:
For part c) it is asking for the net force acting on the car, so I am thinking that I would add the force of the car and the force of the trailer? (I guess the problem is I cannot get the force of the car :-/ )

Hi laurenflakes! :smile:

(I think you're confused about what forces there are, and you're ignoring the force from the car's engine … I know it isn't mentioned in the question :redface:, but sometimes they assume you'll know how cars work :wink:)

a), the trailer, you got it right … net (total) force = ma.

For c), the car, you should do the same thing … net (total) force = ma.

That net force is the force from the trailer plus the force from the engine.

But for b), the car, the force from the trailer can't be found from F = ma, but it can be found from the answer to a), using a different principle … can you see which principle? :smile:
 
  • #5
Hi tiny-tim!

I really appreciate you taking the time to work with me on this.

Im still confused... unfortunately :confused:

In order to submit my answers to these problems I am using an online homework website, and I keep getting the answers wrong.

For part a)
(a) What is the net force exerted by the car on the trailer?

I am multiplying the weight of the car by the acceleration (2.00)(1300), which gives me 2600 N... but the answer is wrong.

For part b)
(b) What force does the trailer exert on the car?

I was able to get this one right by doing the following:

Multiplying the weight of the trailer by the acceleration

(540)(2.00)= 1080N

This is the only part I have been able to get right so far.

For part c)

(c) What is the net force acting on the car?

I tried adding the force of the trailer on the car to the force of the car on the trailer to get the net force... but seeing as I can't seem to get the correct answer for part a.. I can't get the correct answer for this part either.

I am not sure how to calculate the force of the cars engine. Does this have something to do with the acceleration?

When I try to add or subtract the force of the trailer from the car.. I still get the wrong answer?

I'm sorry if I keep repeating myself.. but I really don't understand what I am doing wrong? I really appreciate your patience and contribution tiny-tim! :smile:
 
  • #6
laurenflakes said:
(a) What is the net force exerted by the car on the trailer?

I am multiplying the weight of the car by the acceleration (2.00)(1300), which gives me 2600 N... but the answer is wrong.

For part b)
(b) What force does the trailer exert on the car?

I was able to get this one right by doing the following:

Multiplying the weight of the trailer by the acceleration

(540)(2.00)= 1080N

This is the only part I have been able to get right so far.

Hi laurenflakes! :smile:

ah, now I see where you've gone wrong …

in a), you've used the mass of the car, but you want the force on the trailer, so you have to use F = ma for the trailer, and so m must be the mass of the trailer :wink:

(F is the force on the trailer, m is the mass of the trailer,a nd a is the accleration of the trailer)

in b), you've got the right answer by accident. :biggrin:

Try a) again, and then see if you can see why b) was right! :smile:

(and c) may sort itself out once you've got a) right: tell us if it doesn't)​
 
  • #7
Hey Tiny-Tim!

Yay! I finally got part a) what a relief!

Thank you for your help!

Im still stumped on part c)... it appears to me that by adding the forces in parts a and b you would get the net force that is being asked for in part c)... but that's not the case.. I am still getting the answer wrong :frown:

I'm so frustrated! :confused:

I hope you don't feel like I'm asking you to do the problem for me.. I really do want to understand how to do it on my own.. any guidance?
 
  • #8
laurenflakes said:
Im still stumped on part c)... it appears to me that by adding the forces in parts a and b you would get the net force that is being asked for in part c)...

But c) asks for the net force on the car, while a) is a force on the trailer … so how could a) + b) possibly be the net (or any) force on the car?

I said before: F = ma gives you the net force on the body … just use that for c).

btw, you didn't mention b) just now …

do you know why b) and a) are the same?​
 
  • #9
Yippee! Finally got part c correct. I guess I was thinking too much into it... Thanks for your help :biggrin:

For parts a and b. They are equal because of Newton's Third law of motion which states that forces come in pairs and the forces in a pair act on different objects. So, for any object a exerting a force on object b, object b exerts an equal and opposite force on object a. This is why the force of the car on the trailer and the force of the trailer on the car are equal!


... right? :cool:
 
  • #10
:biggrin: Woohoo! :biggrin:

(just got up :zzz: …)
 

1. What is Newton's Law and how does it apply to a car and trailer?

Newton's Law, also known as the Law of Inertia, states that an object at rest will remain at rest and an object in motion will remain in motion at a constant velocity unless acted upon by an external force. In the case of a car and trailer, this means that the car and trailer will continue moving in the same direction and at the same speed unless a force, such as friction or air resistance, is applied to slow or stop them.

2. How do you calculate the force on a car and trailer using Newton's Law?

The force on a car and trailer can be calculated using the formula F=ma, where F is the force, m is the mass of the car and trailer, and a is the acceleration. This formula can be applied to determine the force needed to change the speed or direction of the car and trailer, as well as to determine the force applied by the car and trailer on any other objects they may come into contact with.

3. What factors can affect the force on a car and trailer?

The force on a car and trailer can be affected by various factors, including the mass and velocity of the car and trailer, as well as external forces such as friction, air resistance, and gravity. Additionally, the distribution of weight and the type of surface the car and trailer are traveling on can also impact the force.

4. How is the force on a car and trailer related to the laws of motion?

The force on a car and trailer is directly related to the laws of motion, specifically Newton's Law of Inertia. This law states that an object will resist changes in its motion, and the force needed to change the motion of an object is directly proportional to its mass and acceleration. In the case of a car and trailer, the force needed to change their motion is affected by their combined mass and the acceleration caused by external forces.

5. Can Newton's Law be used to predict the motion of a car and trailer?

Yes, Newton's Law can be used to predict the motion of a car and trailer. By understanding the forces acting on the car and trailer and using the formula F=ma, scientists and engineers can accurately predict the motion of the car and trailer and make necessary adjustments to ensure safe and efficient travel.

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