- #1
Punkyc7
- 420
- 0
Im curios as to why the inquality is
||x+y||[tex]\leq[/tex]||X||+||y||
but the end of the proof is
=(||x||+||Y||)^2
where does the less than symbol disappear too
||x+y||[tex]\leq[/tex]||X||+||y||
but the end of the proof is
=(||x||+||Y||)^2
where does the less than symbol disappear too