- #1
bayan
- 203
- 0
hi felles.
I am trying to find what is the volume of the [tex]y=\frac{a}{x^2}+b[/tex] is when it is rotated in y-axis.
The values of a is 1 and b is -1.
max hight is 3 and min is 0.
I was trying to integrade and ended up with [tex]V=\frac{-Pi}{y^2+2Y+1}[/tex] where y is 3.
Is this right?
I did a U substitution to integrade [tex]x^2=\frac{1}{y+1}[/tex]
Plz help.
I am trying to find what is the volume of the [tex]y=\frac{a}{x^2}+b[/tex] is when it is rotated in y-axis.
The values of a is 1 and b is -1.
max hight is 3 and min is 0.
I was trying to integrade and ended up with [tex]V=\frac{-Pi}{y^2+2Y+1}[/tex] where y is 3.
Is this right?
I did a U substitution to integrade [tex]x^2=\frac{1}{y+1}[/tex]
Plz help.