- #1
Whatamiat
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Homework Statement
Calculate the motor size required to drive shaft A. (shown in schematic 1 diagram)
Drive shaft rotates at 75 Rpm.
Weight of plunger + attachments = 30kg's
Dimensions of plunger given in schematic 2.
Homework Equations
Work done = F x d (distance = radius of cam x 2 = .6m)
Power = work/time
The Attempt at a Solution
Neglecting the weight of the plunger and attachments to the drive shaft of the motor. I
Just looking at a direct relationship between maximum water displaced and power.
The maximum depth under water (Plunger profile) of 600mm x588 x 1219.2 displaces 215kg of water.
Force = 215 x 9.81 = 2109.15N
Work done = F x d = 2109.5 x.6 = 1265.5J
Power = Work/Time = 1265.5/(.4) = 3164 W or 3.164kW
Would I be right to recalculate this allowing for the weight of the plunger and attachments aiding the displacement of water? eg:
215-30=185kg
F = 185 x 9.81 ...etc?
Is my method here right? or am I way off on how this problem should be calculated?