- #1
peter0516
- 2
- 0
Hard intergration problem!
1. A 20-lb. monkey is attached to a 50-ft. chain that weighs 0.5 lb.
per (linear) foot. The other end of the chain is attached to the
40-ft.-high ceiling of the monkey's cage. Find the amount of work the
monkey does in climbing up her chain to the ceiling.
Teacher said anwser is 1087.5 ft-lb
2. W= f(x)dx
3. i used w= from 0 to 40 .5x+20x...then took antiderivitve and got (1/4)x^2 + 20x=1200 ft-lb
what do i need to do after that i know i need to do the rope from 10 to 40 but idk the formulma
1. A 20-lb. monkey is attached to a 50-ft. chain that weighs 0.5 lb.
per (linear) foot. The other end of the chain is attached to the
40-ft.-high ceiling of the monkey's cage. Find the amount of work the
monkey does in climbing up her chain to the ceiling.
Teacher said anwser is 1087.5 ft-lb
2. W= f(x)dx
3. i used w= from 0 to 40 .5x+20x...then took antiderivitve and got (1/4)x^2 + 20x=1200 ft-lb
what do i need to do after that i know i need to do the rope from 10 to 40 but idk the formulma