- #1
amcavoy
- 665
- 0
For the molecule [tex]\textrm{Ni}\left(\textrm{OH}\right)_{2}\textrm{Cl}\left(\textrm{NH}_{3}\right)_{3}[/tex], how do you determine the number of geometric and optical isomers? I first drew the molecule with a central [tex]\textrm{Cl}[/tex] bonded to three [tex]\textrm{NH}_{3}[/tex] molecules and a [tex]\textrm{Ni}[/tex]; the [tex]\textrm{Ni}[/tex] was in turn bonded to two [tex]\textrm{OH}[/tex] molecules. From this, it appeared that no matter how I moved the atoms surrounding the central atom, the configuration would always be the same; it would just be rotated counterclockwise or clockwise.