- #36
brewnog
Science Advisor
Gold Member
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I think I understand what you're getting at, could you redo the diagram and show more clearly which pipes are connected to what, and which way your check valves operate?
Marijn said:@ lurch and Artman
Again this is external energy.
Being the weight of the lid and the stone (or whatever) on top of the lid.
The case is to NOT use external power.
Absolutely! Of course it has to be done scientifically. Like counting the number of seconds it takes from the time the lid flies off till it strikes the ground (or a passerby) then calculating the height it achieved.Marijn said:in that case the isdea of sealing it and blowing 2000 psi air on top is a helluve lot more fun :D
Civilian2 said:This is the problem in case my explanation hadn't been sufficient.
I'm not attempting to move 1000 kg of water. I'm trying to move as much water as possibly in 20-30 seconds. 10 mL would be enough! As long as I could move some! At the moment, I'm doubting whether I"m going to manage 1mL.
Random said:I had thought this was some sort of logic impossi-puzzle until I read this. Your answer is a hydraulic ram (sold as a "Platypump" in Australia). These devices are not very efficient but are excellent for raising water well beyond the supplied head pressure. For every 10 volumes of water past the pump, 1 volume can be raised to approximately 100 times the supply head pressure. (Great for topping a tank from a lower creek etc.) Hope this helps. Google search the hydraulic ram & you will find plans etc enabling you to build your own for only a few dollars.
brewnog said:But in this case, even getting a tiny amount of water raised would be considered an "adequate result" by Civilian, - see his earlier posts.