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TTob
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order isomorphism f:R-->R
let f is order isomorphism from (R,<) to (R,<). why f is continuous ?
so f is bijection and a<b <--> f(a)<f(b), so what ?
let f is order isomorphism from (R,<) to (R,<). why f is continuous ?
so f is bijection and a<b <--> f(a)<f(b), so what ?