Creation/Ann operators acting on <x|p>

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In summary, the conversation discusses the meaning of a creation or annihilation operator acting on a state, particularly in the context of a free field scalar expressed as a linear sum of these operators. The creation and annihilation operators are transformed into another set of operators dependent on a different variable. The role of the annihilation operator is not to act on anything, but rather to be transformed into an operator that may act on something.
  • #1
LostConjugate
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What does it mean for a creation or annihilation operator to act on the state <x|p>. For example:

[tex] a_p e^{ip \cdot x} [/tex]
 
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  • #2
<x|p>
This is not a state. It's just a number. In the second formula you have an operator multiplied by a number.
 
  • #3
haael said:
This is not a state. It's just a number. In the second formula you have an operator multiplied by a number.

Ok, will try to give it in context.

What does it mean to write a free field scalar as a linear sum of creation and annihilation operators like this?

[tex]

\int \frac{d^3 p}{{(2\pi)}^3}\frac{1}{\sqrt{2\omega_p}} [ a_p e^{ip \cdot x} + a_p^\dagger e^{-ip \cdot x} ]
[/tex]

What is the creation / annihilation operator role in this, it ends up acting on the amplitude...

[tex] a = \sqrt{\frac{\omega}{2}}q + \frac{i}{\sqrt{2\omega}}p [/tex]
 
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  • #4
What does it mean to write a free field scalar as a linear sum of creation and annihilation operators like this?
This is a functional transform, much just like the Fourier transform. You have a bunch of creation/annihilation operators that depend on a parameter p. You transform them into another operator set that depends on x.

Annihilation operators here do not "act" on anything. Rather, they are a subject of transformation. The result of the transformation is another operator that may act on something.
 

1. What is the purpose of "Creation/Ann operators" in quantum mechanics?

The Creation/Annihilation operators are mathematical tools used to describe the creation and destruction of particles in quantum mechanics. They are essential in understanding the behavior of quantum systems and calculating physical quantities such as energy and momentum.

2. How do Creation/Ann operators act on the position and momentum of a particle?

The Creation operator acts on the position state vector |x> and transforms it into a state vector of a particle at position x, while the Annihilation operator does the opposite and transforms the state vector into a state with no particle at position x. The operators also act on the momentum state vector |p> in a similar manner.

3. What is the commutation relationship between Creation/Ann operators and position/momentum operators?

The commutation relationship between Creation/Ann operators and position/momentum operators is given by [a,a†] = 1, where a and a† are the Annihilation and Creation operators respectively. This relationship is crucial in quantum mechanics and is used to derive important properties of quantum systems.

4. Can Creation/Ann operators act on other physical quantities besides position and momentum?

Yes, Creation/Ann operators can act on any observable quantity in quantum mechanics. For example, they can be used to describe the creation and destruction of photons in the field of quantum optics. The operators can also act on spin states in quantum spin systems.

5. How are Creation/Ann operators related to the concept of particle number in quantum mechanics?

The number operator, N, is defined as the product of the Creation and Annihilation operators, N = a†a. This operator represents the number of particles in a given state and is an important quantity in quantum mechanics. The square of the number operator gives the probability of finding a certain number of particles in a specific state.

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