- #1
sgstudent
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Using this graph: http://postimg.org/image/vkv0ho8yb/
As the reaction proceeds it stops at the equilibrium as it has the lowest Gibbs energy. However, I don't understand why ΔG=0 at that point. As shown in the arrow isn't the ΔG greater in magnitude than when the reaction goes to completion? The formula given was ΔG=ΔGstd+RTlnQ so when Q=k ΔG=0. However using the graph I don't see how that is true.
And since all reactions goes to equilibrium, how do we determine how much energy is released? Since at equilibrium, ΔG=0 how can we tell the total amount of energy released after the reaction ends at equilibrium?
Thanks in advance for the help
As the reaction proceeds it stops at the equilibrium as it has the lowest Gibbs energy. However, I don't understand why ΔG=0 at that point. As shown in the arrow isn't the ΔG greater in magnitude than when the reaction goes to completion? The formula given was ΔG=ΔGstd+RTlnQ so when Q=k ΔG=0. However using the graph I don't see how that is true.
And since all reactions goes to equilibrium, how do we determine how much energy is released? Since at equilibrium, ΔG=0 how can we tell the total amount of energy released after the reaction ends at equilibrium?
Thanks in advance for the help