Length of the vector (electrostatic cylinder)


by Blastrix91
Tags: cylinder, electrostatic, length, vector
Blastrix91
Blastrix91 is offline
#1
Nov19-12, 10:04 AM
P: 25


My problem is that I'm confused about a hint I was given in this problem. I usually use the law of cosine to find the length of [itex]\vec{r}-\vec{r'}[/itex]. But the hint here says that I should make it [itex][r^2 + (z - z_0)^2]^{1/2}[/itex]

Where does this come from? I can't quite get my head around the geometrical idea of this hint. Can't the law of cosine be used here?
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mikeph
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#2
Nov19-12, 10:16 AM
P: 1,205
It's really hard to answer these questions when you don't specify what any of the terms mean, so I can only guess at what r-r' even is. It looks like a Pythagoras approach to give you the hypotenuse of the triangle with sides r and z-z0.

How would you use the law of cosine, and what problem would using it solve?
nasu
nasu is offline
#3
Nov19-12, 01:26 PM
P: 1,909
I don't know how the hint is specifically formulated but I think the best way here is to use cylindrical coordinates.
It may be that r' is the cylindrical radius of the charge element.
The point P has r=0 and z=zo.


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