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jrklx250s
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Homework Statement
A current of 10A is maintained for 1s in a resistor of 25Ω while the temperature of the resistor is kept constant at 27°C. This resistor is thermally insulated with a mass of 10g. If it has a specific heat of 836 J/kg*K. What is the entropy change of the resistor? Universe?
Homework Equations
The Attempt at a Solution
Ok so if the wire is thermally insulated at a constant temperature of 27°C, Q=0 therefore
W=0 because it is isothermal and adiabatic
So if entropy is
TdS= dU - dW
so ΔS = 0J/K?
However this is wrong...the answer is 5.78J/K and I am confused at to how they got this... any suggestions?