- #1
dg_5021
- 80
- 0
Hey can someone check if i did it right please. Thanks
At t= 1.0 secs, a 0.40-kg object is falling with a speed of 6.0m/s. At t= 2.0 secs, it has a kinetic energy of 25J. (a) What is the kinetic energy of the object at t= 1.0 secs? (b) What is the speed of the object at t = 2.0 secs? (c) How much work was done on the object between t= 1.0 secs and t= 2.0 secs?
(a) k= (1/2)mv^2
=(1/2)(.40kg)(6.0m/s)^2
= 7.2J
(b) k= (1/2)mv^2
25J = (1/2)(.40kg)(m/s)^2
50J = (.40kg)(m/s)^2
=(125)^(1/2)
= 11.1803m/s
(c) w= (1/2)m11.2^2-(1/2)m6.0^2
=(1/2)m5.2^2
=(1/2)(.40kg)(5.2)^2
=5.36718J
At t= 1.0 secs, a 0.40-kg object is falling with a speed of 6.0m/s. At t= 2.0 secs, it has a kinetic energy of 25J. (a) What is the kinetic energy of the object at t= 1.0 secs? (b) What is the speed of the object at t = 2.0 secs? (c) How much work was done on the object between t= 1.0 secs and t= 2.0 secs?
(a) k= (1/2)mv^2
=(1/2)(.40kg)(6.0m/s)^2
= 7.2J
(b) k= (1/2)mv^2
25J = (1/2)(.40kg)(m/s)^2
50J = (.40kg)(m/s)^2
=(125)^(1/2)
= 11.1803m/s
(c) w= (1/2)m11.2^2-(1/2)m6.0^2
=(1/2)m5.2^2
=(1/2)(.40kg)(5.2)^2
=5.36718J