How Do You Calculate Transformer Losses from Open and Short Circuit Tests?

[alnywk]

urgent: single phase transformer

Homework Statement

A 2200/220 V, 500kVA, 50Hz distribytion transformer has been tested by means of the open circuit. the test data obtained is as follow:
open circuit test: V(l)= 220V, I(l)= 85A, P(oc)= 1800W
short circuit test V(h)=95V, I(h)=227.3A P(sc)= 8.2kW

Homework Equations

1.equivalent resistance referred to the low voltage side (state all assumption)

2. resistance of the low side winding only

3.transformer copper loss of the secondary winding during the open circuit test

4. transformer core loss when rated voltage is applied

5. explain if it justified to use the power input during the open circuit test as core loss?

The Attempt at a Solution

please

 

[Valkarie]

check my answers below.1.equivalent resistance referred to the low voltage side (state all assumption)Assuming that the transformer is single phase, the equivalent resistance referred to the low voltage side can be calculated as follows: R(eq)= V(h)/I(h)= 95/227.3= 0.4179Ω2. resistance of the low side winding onlyR(l)= V(l)/I(l)= 220/85= 2.58Ω3.transformer copper loss of the secondary winding during the open circuit testP(cu,l)= P(oc)-P(sc)= 1800-8200= -6400W4. transformer core loss when rated voltage is appliedP(core)= P(sc)-P(cu,l)= 8200-(-6400)= 14600W5. explain if it justified to use the power input during the open circuit test as core loss?No, it is not justified to use the power input during the open circuit test as core loss as the open circuit test is conducted at no-load condition and hence the core loss is zero.

 

[piercas]

provide more information on the specific questions or calculations needed to answer this prompt. it is important to have clear and specific information in order to provide an accurate and thorough response. Without this information, it is difficult to provide a meaningful answer. Please provide more details on the specific questions or calculations needed. Thank you.