- #1
topper
- 8
- 0
Hey!
I am stuck at a passage in the QFT book of Peskin & Schroeder and I need your help :)
It is about page 698, last break. The sentence is:
"At long wavelength, the Goldstone bosons become infinitesimal symmetry rotations of the vacuum, Q |0> , where Q is the global charge associated with [tex]J^{\mu}[/tex]"
I got two questions:
1. In what sense is the action of Q on a general state corresponding to the gauge transformation of this state? What came into my mind is that [Q,[tex]\phi[/tex]] = [tex]\delta\phi[/tex] (the symmetry generator for the field). But how do I see the argument made in the quote above?
2. What do long wavelength have to do with it?
I hope my question is understandable, I'm a bit in a hurry but I will check the post for misunderstandings later,
thank you,
topper
I am stuck at a passage in the QFT book of Peskin & Schroeder and I need your help :)
It is about page 698, last break. The sentence is:
"At long wavelength, the Goldstone bosons become infinitesimal symmetry rotations of the vacuum, Q |0> , where Q is the global charge associated with [tex]J^{\mu}[/tex]"
I got two questions:
1. In what sense is the action of Q on a general state corresponding to the gauge transformation of this state? What came into my mind is that [Q,[tex]\phi[/tex]] = [tex]\delta\phi[/tex] (the symmetry generator for the field). But how do I see the argument made in the quote above?
2. What do long wavelength have to do with it?
I hope my question is understandable, I'm a bit in a hurry but I will check the post for misunderstandings later,
thank you,
topper