- #1
tomcenjerrym
- 37
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I have 2 questions:
FIRST
I read from John H. Mathews’ Numerical Methods using MATLAB, 3E that the number
1563 can be expanded in form of 10-base expansion as:
(1 × 10[tex]^{3}[/tex]) − (5 × 10[tex]^{2}[/tex]) + (6 × 10[tex]^{1}[/tex]) + (3 × 10[tex]^{0}[/tex]) …......... (1)
Which results 1000 − 500 + 60 + 3 equal to 563.
But the number 1563 should be expanded in form of 10-base expansion as:
1563 = 1000 + 500 + 60 + 3
Which means:
(1 × 10[tex]^{3}[/tex]) + (5 × 10[tex]^{2}[/tex]) + (6 × 10[tex]^{1}[/tex]) + (3 × 10[tex]^{0}[/tex]) …......... (2)
Hence, (1) ≠ (2) or 1563 ≠ 563.
So, can anyone explain me about these?
SECOND
If the number 1563 is expressible in expanded form of 10-base expansion as:
1563 = 1000 + 500 + 60 + 3
=(1 × 10[tex]^{3}[/tex]) − (5 × 10[tex]^{2}[/tex]) + (6 × 10[tex]^{1}[/tex]) + (3 × 10[tex]^{0}[/tex])
how can I express the number 1563 in expanded form of 2-base expansion?
Please advance
FIRST
I read from John H. Mathews’ Numerical Methods using MATLAB, 3E that the number
1563 can be expanded in form of 10-base expansion as:
(1 × 10[tex]^{3}[/tex]) − (5 × 10[tex]^{2}[/tex]) + (6 × 10[tex]^{1}[/tex]) + (3 × 10[tex]^{0}[/tex]) …......... (1)
Which results 1000 − 500 + 60 + 3 equal to 563.
But the number 1563 should be expanded in form of 10-base expansion as:
1563 = 1000 + 500 + 60 + 3
Which means:
(1 × 10[tex]^{3}[/tex]) + (5 × 10[tex]^{2}[/tex]) + (6 × 10[tex]^{1}[/tex]) + (3 × 10[tex]^{0}[/tex]) …......... (2)
Hence, (1) ≠ (2) or 1563 ≠ 563.
So, can anyone explain me about these?
SECOND
If the number 1563 is expressible in expanded form of 10-base expansion as:
1563 = 1000 + 500 + 60 + 3
=(1 × 10[tex]^{3}[/tex]) − (5 × 10[tex]^{2}[/tex]) + (6 × 10[tex]^{1}[/tex]) + (3 × 10[tex]^{0}[/tex])
how can I express the number 1563 in expanded form of 2-base expansion?
Please advance