- #1
StephenPrivitera
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The book and I aren't getting along tonight. Maybe you can help.
A rope of length L has a tension T. Someone pushes on the rope with a force F at its midpoint and deflects the rope by a distance d. What is T is terms of L,d and F.
This is so simple I won't even explain my work.
2Tsinθ=F
sinθ=d/(L/2)=2d/L (approx)
so
[tex]T=\frac{FL}{4d}[/tex]
Right?
The prob. in the book had numbers, but in the end I was off by a factor of 2.
A rope of length L has a tension T. Someone pushes on the rope with a force F at its midpoint and deflects the rope by a distance d. What is T is terms of L,d and F.
This is so simple I won't even explain my work.
2Tsinθ=F
sinθ=d/(L/2)=2d/L (approx)
so
[tex]T=\frac{FL}{4d}[/tex]
Right?
The prob. in the book had numbers, but in the end I was off by a factor of 2.