- #1
Niles
- 1,866
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Hi
The dispersion of Bogolyubov quasiparticles in a d-wave superconductor is
[tex]
E(\mathbf k) = \pm \sqrt{\varepsilon (\mathbf k)^2+\Delta (\mathbf k)^2},
[/tex]
where ε(k) is the normal-state dispersion and ∆(k) is the gap dispersion. My question is: The Fermi surface (FS) of the normal state is just ε(k). Is this also the FS of the superconductor?
The dispersion of Bogolyubov quasiparticles in a d-wave superconductor is
[tex]
E(\mathbf k) = \pm \sqrt{\varepsilon (\mathbf k)^2+\Delta (\mathbf k)^2},
[/tex]
where ε(k) is the normal-state dispersion and ∆(k) is the gap dispersion. My question is: The Fermi surface (FS) of the normal state is just ε(k). Is this also the FS of the superconductor?