- #1
KatieLynn
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Homework Statement
An arrow is shot at 42 degrees from the horizontal to strike a target that is 53 meters away and at the same elevation as the archer. What is the initial velocity?
Homework Equations
I'm not sure which equation(s) is/are needed so I'll list all the ones I can...
(Vix)=(CosX)
x=(Vix)(t)
(Vxf)=(Vxi)
(-Vi)(SinX) = (Vi)(SinX) + (g)(t)
(-2Vfy)=(g)(t)
(Vfy)^2=(Viy)^2 + 2(g)(y)
g=-9.81 m/s
The Attempt at a Solution
I don't know how to solve it. All the information you are given is theta = 42 and the X distance is 53 m, I don't see how you can use any of those equations to solve for anything with only those two pieces of information.