Derivative of f(x)= x+sqrt(x) - Domain & Derivative

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In summary, the function f(x)= x+sqrt(x) has a domain of all real numbers greater than or equal to 0, a derivative of 1+ 1/(2sqrt(x)), and a point of inflection at x=0. The significance of the derivative in this function is that it represents the rate of change at any given point on the curve and the function itself is continuous without any breaks or jumps.
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Homework Statement



Find the derivative of the function using the definition of derivative. state the domain of the function and the derivative.

f(x)= x +sqrt(x)

The Attempt at a Solution



lim f(x)= [x+h+sqrt(x+h) -x -sqrt(x)]/h
h-->0

limf(x)=[h + sqrt(x+h) - sqrt(x)]/h
h->0

not sure how to proceed?
 
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  • #2
Separate out the h/h term and rationalize the numerator in what is left.
 

FAQ: Derivative of f(x)= x+sqrt(x) - Domain & Derivative

What is the domain of the function f(x)= x+sqrt(x)?

The domain of f(x)= x+sqrt(x) is all real numbers greater than or equal to 0. This is because the square root function is only defined for non-negative numbers.

What is the derivative of f(x)= x+sqrt(x)?

The derivative of f(x)= x+sqrt(x) is 1+ 1/(2sqrt(x)). This can be found using the sum rule and the power rule for derivatives.

What is the significance of the derivative in this function?

The derivative of a function represents the rate of change of the function at a specific point. In this case, the derivative of f(x)= x+sqrt(x) tells us how the function is changing at any given point along the curve.

Is the function f(x)= x+sqrt(x) continuous?

Yes, the function f(x)= x+sqrt(x) is continuous. This means that there are no breaks or jumps in the graph of the function and it can be drawn without lifting the pen.

Are there any points of inflection in the graph of f(x)= x+sqrt(x)?

Yes, there is a point of inflection at x=0 in the graph of f(x)= x+sqrt(x). This is because the second derivative of the function changes sign at this point, indicating a change in concavity of the graph.

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