- #1
rdn98
- 39
- 0
An infinite nonconducting sheet of charge, oriented perpendicular to the x-axis, passes through x = 0. It has area density s1 = -3 µC/m2. A thick, infinite conducting slab, also oriented perpendicular to the x-axis, occupies the region between x = a and x = b, where a = 3 cm and b = 4 cm. The conducting slab has a net charge per unit area of s2 = 4 µC/m2.
a picture is added below
===============
(b) Calculate the surface charge densities on the left-hand (sa) and right-hand (sb) faces of the conducting slab.You may also find it useful to note the relationship between sa and sb.
sa=?
sb=?
where s stands for sigma
==========
Ok, so I need to figure out the two indivudal surface charges, that will give me the net overall surface charge density.
I know that E=sigma/ (2*epislon)
where E = electric field
epislon= 8.85e-12
I can figure out the electric field values between the two slabs, and the electric fields to the right of the conducting slab.
Total Electric field for slab 1 = sigma_1/(2*epsilon) = -1.69E5 N/C =E_left
Total Electric field from slab 2 is sigam_2/(2*epsilon) = 2.25E5 N/C = E_right
now, I tried setting up this equation
for the left side of slab 2
-E_right+E_left=(sigma_1+sigma_2)/(2*epsilon)
now to the right side of slab 2
E_right+E_left=(sigma_1+sigma_2)/(2*epsilon)
so its a system of equations..but when I solve for one sigma, it totally cancels itself out when plugged into the other equation..I've been at this stupid problem for almost an hour and half..how do I finish this ?
a picture is added below
===============
(b) Calculate the surface charge densities on the left-hand (sa) and right-hand (sb) faces of the conducting slab.You may also find it useful to note the relationship between sa and sb.
sa=?
sb=?
where s stands for sigma
==========
Ok, so I need to figure out the two indivudal surface charges, that will give me the net overall surface charge density.
I know that E=sigma/ (2*epislon)
where E = electric field
epislon= 8.85e-12
I can figure out the electric field values between the two slabs, and the electric fields to the right of the conducting slab.
Total Electric field for slab 1 = sigma_1/(2*epsilon) = -1.69E5 N/C =E_left
Total Electric field from slab 2 is sigam_2/(2*epsilon) = 2.25E5 N/C = E_right
now, I tried setting up this equation
for the left side of slab 2
-E_right+E_left=(sigma_1+sigma_2)/(2*epsilon)
now to the right side of slab 2
E_right+E_left=(sigma_1+sigma_2)/(2*epsilon)
so its a system of equations..but when I solve for one sigma, it totally cancels itself out when plugged into the other equation..I've been at this stupid problem for almost an hour and half..how do I finish this ?