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odolwa99
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In attempting this question, I decided to expand the first statement. Can anyone help me out?
Many thanks.
If [itex]\sin A=\sin(A+30^{\circ})[/itex], show that [itex]\tan A=2+\sqrt{3}[/itex].
[itex]\sin A=\sin A\cos30+\cos A\sin30[/itex]
[itex]\sin A=\frac{\sin A\sqrt{3}+\cos A}{2}[/itex]
[itex]2\sin A=\sin A\sqrt{3}+\cos A[/itex]
[itex]\sin A(2-\sqrt{3})=\cos A[/itex]
[itex]2-\sqrt{3}=\frac{\cos A}{\sin A}[/itex]
Many thanks.
Homework Statement
If [itex]\sin A=\sin(A+30^{\circ})[/itex], show that [itex]\tan A=2+\sqrt{3}[/itex].
Homework Equations
The Attempt at a Solution
[itex]\sin A=\sin A\cos30+\cos A\sin30[/itex]
[itex]\sin A=\frac{\sin A\sqrt{3}+\cos A}{2}[/itex]
[itex]2\sin A=\sin A\sqrt{3}+\cos A[/itex]
[itex]\sin A(2-\sqrt{3})=\cos A[/itex]
[itex]2-\sqrt{3}=\frac{\cos A}{\sin A}[/itex]
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