- #1
r_swayze
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(a) What is the magnitude of the current that flows through branch AB? (b) In what direction does the conventional current flow in branch AB? (c) What is the magnitude of the current that flows through branch CD? (d) In what direction does the conventional current flow in branch CD?
I don't know where to start with this problem since there are 3 batteries in two different loops.
I think in the first loop the circuit would be 1.5 A, since 10V + 5V = 15V, and 15V/10ohm = 1.5 A?
And then, for the second loop 4V - I*7ohm - I*10ohm = 0. That circuit would be 0.235 A.
magnitude of the branch AB would be 1.5A + 0.235A = 1.735A
Am I doing this correctly?
and for part d) why is the magnitude of the current flowing to the right? shouldn't it be flowing left since the positive terminal of the battery is on the left side of the negative terminal?
I don't know where to start with this problem since there are 3 batteries in two different loops.
I think in the first loop the circuit would be 1.5 A, since 10V + 5V = 15V, and 15V/10ohm = 1.5 A?
And then, for the second loop 4V - I*7ohm - I*10ohm = 0. That circuit would be 0.235 A.
magnitude of the branch AB would be 1.5A + 0.235A = 1.735A
Am I doing this correctly?
and for part d) why is the magnitude of the current flowing to the right? shouldn't it be flowing left since the positive terminal of the battery is on the left side of the negative terminal?