- #1
an_mui
- 47
- 0
Two large parallel copper plates are 5.0cm apart and have a uniform eletric field between them as shown below. An electron is released from the negative plate at the same time that a proton is released from the positive plate. Neglect th force of the particles on each other and find their distance from the positive plate when they pass each other.
proton ->
electron <--
F = ma
Force is constant, so acceleration is proportional to 1 / m
d = distance from positive plate
1. d = 0.5a1t^2
2. d = 0.05 - 0.5 a2t^2
can someone check my progress so far? I am really stuck on this question. I am still not very good at the concept of electric field and electric potential
proton ->
electron <--
F = ma
Force is constant, so acceleration is proportional to 1 / m
d = distance from positive plate
1. d = 0.5a1t^2
2. d = 0.05 - 0.5 a2t^2
can someone check my progress so far? I am really stuck on this question. I am still not very good at the concept of electric field and electric potential